Exponential function of a complex number question?

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SUMMARY

The discussion focuses on calculating the exponential function of a complex number using the formula e^(a + bi) = e^a (cos b + i sin b). The specific values provided are a = 5 and b = 5π/6. The solution derived is e^(5 + 5iπ/6) = e^5 (-√3/2 + i/2), confirming the use of Euler's formula for complex exponentiation. The participant seeks further guidance on subsequent steps in the problem-solving process.

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Mandynash
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Homework Statement



The question is located here http://i51.tinypic.com/nex2q1.jpg

Homework Equations



The value I have been given for a) is 5
The value I have been given for b) is 5PI/6

The Attempt at a Solution



Note that e^(a + bi) = e^a e^(bi) = e^a (cos b + i sin b).
(e^a is the modulus, and b is the argument, because |e^(bi)| = sqrt(cos^2(b) + sin^2(b)) = 1.)

Letting a = 5 and b = 5π/6 yields
e^(a+bi) = e^5 (cos 5π/6 + i sin 5π/6) = e^5 (-sqrt(3)/2 + i/2).

No idea what else I need to do! thanks in advance for helping
 
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