Exponential function sum problem

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
rustyjoker
Messages
5
Reaction score
0

Homework Statement


I need to prove that
(1+[itex]x_{1})[/itex]·...·(1+[itex]x_{n}[/itex])≥(1-[itex]Ʃ^{n}_{i=1}x_{i}^2[/itex])[itex]e^{Ʃ^{n}_{i=1}x_{i}}[/itex]
with all 0≤[itex]x_{i}[/itex]≤1

I've already proven that

(1+[itex]x_{1}[/itex])·...·(1+[itex]x_{n}[/itex])≤[itex]e^{Ʃ^{n}_{i=1}x_{i}}[/itex]
with all 0≤[itex]x_{i}[/itex]≤1

and (1-[itex]x_{1}[/itex])·...·(1-[itex]x_{i}[/itex])≥1-Ʃ[itex]^{n}_{i=1}x_{i}[/itex] with all 0≤[itex]x_{i}[/itex]≤1 ,

but can't figure out what to do with the main problem :D
 
Physics news on Phys.org
rustyjoker said:

Homework Statement


I need to prove that
(1+[itex]x_{1})[/itex]·...·(1+[itex]x_{n}[/itex])≥(1-[itex]Ʃ^{n}_{i=1}x_{i}^2[/itex])[itex]e^{Ʃ^{n}_{i=1}x_{i}}[/itex]
with all 0≤[itex]x_{i}[/itex]≤1

I've already proven that

(1+[itex]x_{1}[/itex])·...·(1+[itex]x_{n}[/itex])≤[itex]e^{Ʃ^{n}_{i=1}x_{i}}[/itex]
with all 0≤[itex]x_{i}[/itex]≤1

and (1-[itex]x_{1}[/itex])·...·(1-[itex]x_{i}[/itex])≥1-Ʃ[itex]^{n}_{i=1}x_{i}[/itex] with all 0≤[itex]x_{i}[/itex]≤1 ,

but can't figure out what to do with the main problem :D

Take logarithm on both sides, i.e.,
Ʃ log(1+x_i)≥log(1-Ʃ x_i^2)+Ʃ x_i
then realize that x(1-x)≤log(1+x)≤x for 0<x<1, substitute in and you'll see
 
you can't take logarithm because you can't know if 1-sum(x_i)^2 is negative or not.