Exponential growth of populations (Q=Ae^kt)

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SUMMARY

The exponential growth of a rabbit population is modeled by the equation N=80e^(0.02t), where N represents the number of rabbits and t is time in days. To determine when the population reaches 500 rabbits, the equation 80e^(0.02t) = 500 must be solved. The correct approach involves dividing both sides by 80, leading to e^(0.02t) = 6.25, followed by taking the natural logarithm of both sides. This results in t = ln(6.25)/0.02, which calculates to approximately 92 days.

PREREQUISITES
  • Understanding of exponential functions and growth models
  • Familiarity with natural logarithms and their properties
  • Basic algebra skills for manipulating equations
  • Knowledge of the formula Q=Ae^kt for exponential growth
NEXT STEPS
  • Review how to solve exponential equations using logarithms
  • Practice problems involving population growth models
  • Learn about the implications of exponential growth in real-world scenarios
  • Explore variations of the exponential growth formula for different contexts
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Students studying algebra, biology enthusiasts interested in population dynamics, and educators teaching exponential growth concepts.

Alistair
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Homework Statement


The number of rabbits in a colony is given by N=80e^(0.02t) where t is in days.
c) After how many days will there be 500 rabbits?

N=500
A=80
k=0.02
t=?

Homework Equations


(ln being the exponential logarithm)
Q=Ae^kt
and possibly the conversion formula: ln y = x --> y=e^x

The Attempt at a Solution



what i tried was coverting Q=Ae^kt to A ln Q=kt
Then divided both sudes by x to give:

A ln Q = t
k


Which after substitution looked like this:

80 ln 500 = t
0.02

Which gave t=24,858 days.
where as the answer is 92 days...
 
Last edited:
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Alistair said:

Homework Statement


The number of rabbits in a colony is given by N=80e^(0.02t) where t is in days.
c) After how many days will there be 500 rabbits?

N=500
A=80
k=0.02
t=?

Homework Equations


(ln being the exponential logarithm)
Q=Ae^kt
and possibly the conversion formula: ln y = x --> y=e^x

The Attempt at a Solution



what i tried was coverting Q=Ae^kt to A ln Q=xt
Then divided both sudes by x to give:

A ln Q = t
x
This equation is wrong. Perhaps you are getting confused with your variables; there's no reason to introduce x, stick with A, k and t and try again.
 
marcusl said:
This equation is wrong. Perhaps you are getting confused with your variables; there's no reason to introduce x, stick with A, k and t and try again.

Yeah i ment k not x.
in my maths book in the examples it has x. but it still doesn't work with k in there... :frown:
 
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.
 
danago said:
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.

i don't know how dividing both sides by 80 will make it easier or alter the answer in any way...
i want to know if there is a problem with my working. I am not sure if it is even the right formula...
 
Alistair said:
Yeah i ment k not x.
in my maths book in the examples it has x. but it still doesn't work with k in there... :frown:
If you really believe that using the letter "x" gives you a different equation that using the letter "k", you need to review basic algebra!

danago said:
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.

Alistair said:
i don't know how dividing both sides by 80 will make it easier or alter the answer in any way...
i want to know if there is a problem with my working. I am not sure if it is even the right formula...

You have already been told that there is a problem with your "working"!

You are given the formula N= 80e^{0.02t} so of course, that the correct formula. You are also told that N= 500 so the equation you want to solve is 80 e^{0.02t}= 500. Surely, it would be an obvious first step to divide both sides by 80? After you have done that take the natural logarithm of both sides.
 
ok got it.
500 = 80e^0.02t
goes to
ln 6.25 = t
0.02
 
Okay, now, what is your answer to the question?
 

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