Exponential of hypercomplex numbers

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Discussion Overview

The discussion revolves around the properties of the exponential function when applied to hypercomplex numbers, specifically quaternions and octonions. Participants explore whether the exponential of these numbers yields results within the same number system and examine the implications of non-commutativity in these contexts.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant questions if the exponential of a quaternion results in a quaternion and similarly for octonions.
  • Another participant suggests using the infinite series definition of the exponential to investigate the properties of these hypercomplex numbers.
  • A later reply discusses the Taylor series for the exponential function, noting that while the linear approximation remains valid, the non-commutativity of quaternions and octonions complicates the situation, particularly for odd-numbered exponents.
  • One participant provides a detailed formulation of a quaternion and its properties, including its conjugation and norm, and presents a series expression for the exponential of a quaternion, concluding that it appears to yield a quaternion.
  • This participant also posits that a similar reasoning could apply to octonions, suggesting that the exponential of an octonion would also be an octonion.

Areas of Agreement / Disagreement

There is no clear consensus among participants. While some suggest that the exponential of quaternions and octonions remains within their respective number systems, others raise questions about the implications of non-commutativity and the validity of these claims.

Contextual Notes

Participants express uncertainty regarding the effects of non-commutativity on the exponential function, particularly for odd-numbered exponents. The discussion also highlights the dependence on the definitions and properties of hypercomplex numbers.

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The exponential of a complex number is a complex number. Does this extent to the quaternions and the octonions? Does the exponential of a quaternion give a quaternion? Does the exponential of an octonion give an octonion? Thanks.
 
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try the infinite series definition of exponential. what happens?
 
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mathwonk said:
try the infinite series definition of exponential. what happens?
The Taylor series for the exponential is,

{e^x} = 1 + \frac{x}{{1!}} + \frac{{{x^2}}}{{2!}} + \frac{{{x^3}}}{{3!}} + \frac{{{x^4}}}{{4!}} + ...

So obviously the linear approximation for the exponential will be the same as the exponent. If the exponent is a quaternion, then the linear approximation will be a quaternion, and same goes for the octonions. However, the quaternions and octonions do not commute. I think this means that you can still get a quadratic approximation (correct me if I'm wrong), but odd numbered exponents will have two ways of being expressed, depending on whether you multiply from the left or right. So I don't know what to say about this.
 
I learn from Wikipedia that a quaternion can be written generally as

q = {x_0} + i{x_1} + j{x_2} + k{x_3},

where {x_0}, {x_1}, {x_2}, {x_3} are real numbers. And {i^2} = {j^2} = {k^2} = - 1

Its conjugation is written,

{q^*} = {x_0} - i{x_1} - j{x_2} - k{x_3}.

Its norm can be written,

\left\| q \right\| = \sqrt {q{q^*}} = \sqrt {{x_0}^2 + {x_1}^2 + {x_2}^2 + {x_3}^2}.

But q can also be written as a scalar plus a vector as,

q = {x_0} + \vec v,

where,

\vec v = i{x_1} + j{x_2} + k{x_3}.

Then the exponential of a quaternion, q, can be written as,

{e^q} = \sum\limits_{n = 0}^\infty {\frac{{{q^n}}}{{n!}} = {e^{{x_0}}}(\cos \left\| {\vec v} \right\|} + \frac{{\vec v}}{{\left\| {\vec v} \right\|}}\sin \left\| {\vec v} \right\|).

So since the {\vec v} carries the i, j, k components, it does indeed seem that the exponential of a quaternion is a quaternion.

I assume the same construction leads to the fact that the exponential of a octonion is an octonion.
 

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