Expressing Quadratic Equations in Different Forms

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The quadratic equation x^2 - 6x + 20 can be expressed in different forms to find the sums and products of its roots. It is established that α + β equals 6 and αβ equals 20. To find α^2 + β^2, the equation 36 = α^2 + β^2 + 2αβ is used, leading to the result that α^2 + β^2 equals -4. The discussion highlights the importance of defining the roots α and β for clarity in calculations. The final conclusion is that α^2 + β^2 results in a negative value, which is significant in the context of quadratic equations.
chwala
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Homework Statement


Express the quadratic equation ##x^2-6x+20## in the different form hence find,## 1. α+β, αβ , α^2+β^2##

Homework Equations

The Attempt at a Solution


## -(α+β)= -6 ⇒α+β= 6, αβ=20##
[/B]
now where my problem is finding ##α^2+β^2## , i don't have my reference notes here ...hint please
 
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You will need to define ##\alpha## and ##\beta##. How else are we to know what they are?
 
hint is ##(a+b)^2=6^2=a^2+b^2+2ab##
 
Ok let the roots of a qaudratic equation be ##x=α , x=β→ (x-α)(x-β)## are factors of a quadratic function thus on expanding
## x^2-(α+β)x+αβ = x^2-6x+20##
 
Thanks Delta...let me see now
 
we have ##36=α^2+β^2+2αβ, →36=α^2+β^2+40, → α^2+β^2= -4##
 
Greetings from Africa Chikhabi from East Afica, Kenya.
 
chwala said:
we have ##36=α^2+β^2+2αβ, →36=α^2+β^2+40, → α^2+β^2= -4##
Yes.
 

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