Expressing the binomial coefficients

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Homework Help Overview

The discussion revolves around expressing binomial coefficients in terms of factorials and simplifying the expression. The original poster seeks assistance in understanding how to approach the problem and the relevant definitions involved.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of nCr and its relation to factorials. Questions arise about the multiplication of terms and the correct interpretation of expressions involving binomial coefficients.

Discussion Status

Some participants have provided guidance on using the definition of nCr and suggested simplification steps. There is an ongoing exploration of how to manipulate the expressions correctly, with hints offered for further simplification.

Contextual Notes

The original poster expresses uncertainty about how to start the problem and the specific algebraic manipulations required. There is a focus on ensuring clarity in the definitions and operations involving factorials.

vanitymdl
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Homework Statement


Expressing the binomial coefficients in terms of factorials and simplifying algebraically, show that
(n over r) = (n-r+1)/r (n over r-1);

Homework Equations


The Attempt at a Solution


I honestly don't even know how to come about this problem...I really need help in this subject. Even how to start it would be great.
 
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Hey vanitymdl and welcome to the forums.

What is the definition of nCr? Try using this definition and then simplify as much as you can. If you get stuck show us what you have done so you can get suggestions.

I'll get you started by saying that nCr = n! / [r! * (n - r)!] where x! is x factorial (i.e. you multiply all numbers from 1 to x and returns the result for x!). We also define 0! to be 1 and don't consider negative factorials to exist.
 
I guess that part that is confusing me is how can I multiply (n-r+1)/r (n over r-1)?
 
vanitymdl said:
I guess that part that is confusing me is how can I multiply (n-r+1)/r (n over r-1)?

By this do you mean [(n-r+1)/r] * nC(r-1) or (n-r+1) / [r * nC(r-1)] (or something else)?
 
chiro said:
By this do you mean [(n-r+1)/r] * nC(r-1) or (n-r+1) / [r * nC(r-1)] (or something else)?

I mean, [(n-r+1)/r] * nC(r-1). So how would I come about that?
 
Since nC(r-1) = n! / [(r-1)! * (n - r + 1)!] then you have

[n-r+1]/r * nC(r-1) = n! * (n-r+1)/[r*(r-1)! * (n-r+1)!]

Now r*(r-1)! = r! and (n-r+1)/(n-r+1)! = 1/(n-r)! (you can just expand the factorial).

Using these hints, can you simplify further?
 
And Yes you can... so the [n-r+1]/r * nC(r-1) will simplify to n!/r!(n-r)!

So this will lead me to the nCr which is n!/r!(n-r)!
 

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