Expression of the force derived from this potential

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To express the force derived from a potential function U(r, θ, φ), the force on a test charge q is given by the equation F = -q∇U. The gradient ∇U must be calculated, typically in spherical coordinates, using the formula ∇U = ∂U/∂r ȷ + (1/r)(∂U/∂θ) ȷ + (1/(r sin θ))(∂U/∂φ) ȷ. In this specific case, since U does not depend on θ and φ, the gradient simplifies significantly. Calculating the gradient accurately is essential for determining the force in the field. Understanding these steps will guide the application of the potential function to find the corresponding force.
Andrei0408
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Homework Statement
Knowing that the potential is U = - α / r , where α is a positive constant and r the distance from the
potential field source, find the expression of the force deriving from this potential; Give examples of forces that derive from such a potential.
Relevant Equations
Not sure
I just don't know what equations I should use, or what exactly I need to do. I just need some guidelines, thank you!
 
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It is a well known fact that given the potential function ##U(r,\theta,\phi)## of a field , the force that the field applies to a test point charge (or test point mass or whatever is the field subject)## q## is given by $$\vec{F}=-q\nabla U$$.

So all you have to do is calculate the gradient ##\nabla U## of the function ##U##. I assume from the context that the calculation must be done in spherical coordinates. So it will be $$\nabla U=\frac{\partial U}{\partial r}\hat r+\frac{1}{r}\frac{\partial U}{\partial \theta}\hat\theta+\frac{1}{r\sin\theta}\frac{\partial U}{\partial \phi}\hat\phi$$

Also note that in your case the function U does not depend on ##\theta## and ##\phi## so the above formula for the gradient of U simplifies a lot.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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