(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

solid, uniform disk of mass M and radius a may be rotated about any axis parallel to the disk axis, at variable distances from the center of the disk

If you use this disk as a pendulum bob, what is T(d), the period of the pendulum, if the axis is a distance d from the center of mass of the disk?

and

The period of the pendulum has an extremum (a local maximum or a local minimum) for some value of d between zero and infinity. Is it a local maximum or a local minimum?

2. Relevant equations

From the picture, I come up with the moment of inertia of the solid disk around its center of mass

I = 1/2Ma^2

From the question, we are asked to find the period of the pendulum if the axis distance d from the center of mass.

The period T for this is P= 2pi (sqrt L/g) where g is the gravitation force

and L is the lenght.

From my understanding is that because of the new lenght, we need to use the Parallel Theorem to find the new lenght

I am not sure about this, so hope someone can help

Iend = Icm + Md^2

Iend = 1/2Ma^2 + Md^2

So the period is P = 2pi (sqrt(( a^2 +d^2)/g))

But this is not correct.

Thank

**Physics Forums - The Fusion of Science and Community**

# Extreme Period for a Physical Pendulum

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Extreme Period for a Physical Pendulum

Loading...

**Physics Forums - The Fusion of Science and Community**