We have a continuous bijection f:X-->Y.(adsbygoogle = window.adsbygoogle || []).push({});

Prove that if f is open, then f inverse is continuous.

I can't figure it out.

"Proof". For V open in Y, there exists W open in X such that [tex]f[W] \subseteq V[/tex]. Where does the f is open definition apply?

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# Homework Help: F is an open mapping implies f inverse cont.

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