F=ma prob with electrons (They don't even act like particles )

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Homework Help Overview

The discussion revolves around a problem involving the acceleration of electrons in an oscilloscope, where a constant force is applied. Participants are exploring the implications of using Newton's second law (F=ma) in the context of a group of electrons and the challenges posed by the unknown total mass.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the acceleration of individual electrons versus a group, questioning how to interpret the given force and its application to the mass of multiple electrons. There is uncertainty about how to proceed without knowing the number of electrons involved.

Discussion Status

Some participants suggest treating each electron separately, while others express concern about the ambiguity of the problem's phrasing regarding the force applied to a group of electrons. The conversation reflects a mix of interpretations and attempts to clarify the problem's setup.

Contextual Notes

There is a noted lack of information regarding the number of electrons, which complicates the calculation of total mass and subsequent acceleration. Participants are grappling with the implications of the problem's wording and the assumptions that can be made.

Pee-Buddy
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F=ma prob with electrons (They don't even act like particles!)

Well here's the problem:

1. Electrons in an oscilloscope are accelerated from rest by a constant force of 8.0*10^16 N over a distance of 15mm. Find (a) the acceleration and (b) the final velocity.


Relevant equations:
2. F=ma, v^2+u^2=2as, v=ut+1/2at^2

At any rate it's easy to find the acceleration of 1 electron, but I don't know how to obtain the mass of all of them. I tried to find the force needed to displace a mass of 1 electron (9.1093897*10^-31 kg) by 15mm and then simply cross multiplying the forces and accelerations, but since I don't know the time (since I don't know the speed of the electron) I'm flumoxed!

3. The Attempt at a Solution :
F=ma => a= (8*10^16 N)/m(total)

a= (8*10^16 N)/(9.1093897*10^-31)x ;where is x =total no. of electrons

ax = 8.782147641^46 m/s^2


Again the final velocity is easy to get once I've gotten the acceleration. Any help would be appreciated.
 
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Treat each electron separately. Presumably, you are given the force on each electron, so find their acceleration.
 
Agreed..
 
Unfortunately, you're only given the force acting on a group of electrons of unknown size.
Sure if I knew the force acting on each electron it'd be easy!
 
Pee-Buddy said:
Unfortunately, you're only given the force acting on a group of electrons of unknown size.
Sure if I knew the force acting on each electron it'd be easy!
You are over-interpreting the phrasing of the problem. It is easy! When they say: "Electons are..." they are talking about each electron. (Just like saying "Electrons have a mass of ...". How many electrons? One!)

Otherwise you would be correct: The problem would be impossible. A given force is exerted on an unknown mass. Find the acceleration. Sorry, no can do! :wink:
 

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