F(x) = e^(2x) and g(x) = lnx. what is the derivative of f(g(x)) at x=e

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SUMMARY

The derivative of the composite function f(g(x)) where f(x) = e^(2x) and g(x) = ln(x) is calculated using the chain rule. The first step involves determining f'(x) = 2e^(2x) and g'(x) = 1/x. At x = e, g(e) = 1, leading to f'(g(e)) = f'(1) = 2e^2. Therefore, the derivative at x = e is 2e^2 * (1/e) = 2e.

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Homework Statement


f(x) = e^(2x) and g(x) = lnx. what is the derivative of f(g(x)) at x=e


Homework Equations


dy/dx = f'g(x) x g'(x)


The Attempt at a Solution


i can't figure it out!
 
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Try it! What's f'(x)? g'(x)? f'(g(x))?
 
remember your chain rule:
[f(g(x))]'=f'(g(x))\cdot g'(x)
take each derivative separately and put it all together if it seems too complicated, that helps me a lot
 

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