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f'(x)=sin((pi (e^x)) /2) and f(0)=1 then f(2)= ?
so i integrate and get -(1/((pi/2)*e^x)) cos((pi (e^x)) /2)+ 1=1
when i plug two into that i don't get any of the answers listed
a)-1.819
b) -.843
c.) -.819
d) .157
e) 1.157
so i integrate and get -(1/((pi/2)*e^x)) cos((pi (e^x)) /2)+ 1=1
when i plug two into that i don't get any of the answers listed
a)-1.819
b) -.843
c.) -.819
d) .157
e) 1.157