Faling to loop the loop in a rollercoaster. How does this happen?

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A rollercoaster can fail to complete a loop if its speed decreases significantly, leading to insufficient centripetal force. At the top of the loop, the required centripetal force is the sum of the weight and the contact force from the seat. If the velocity drops, the contact force diminishes and can reach zero, meaning the only force acting is gravity. When the weight exceeds the required centripetal force, the rider will fall downwards, following a parabolic trajectory rather than dropping straight down. Understanding this motion involves applying Newton's second law and recognizing the relationship between velocity, centripetal force, and gravitational force.
shahir_elmadr
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Homework Statement



At the top of the loop, we are in an upside down position, with our head being pointed towards the centre of the circle. As long as the ride is fast enough, it's impossible for us to fall out. But what happens if the ride slows down? if the rollercoaster slows down, the centripetal force is smaller. Which means the contact force from the seat will be smaller, right? if the velocity decreases further, the contact force at the top decreases to zero, since centripetal force is the sum of weight + contact/reaction force. If the rollercoaster slows down even further and the weight becomes greater than the required centripetal force, we are supposed to fall down.

Homework Equations



Why do we fall down if the weight becomes greater than the centripetal force? What is the physics behind this motion?

The Attempt at a Solution

 
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welcome to pf!

hi shahir_elmadr! welcome to pf! :smile:

apply good ol' Newton's second law …

Ftotal = ma :wink:

to keep moving in a circle, you must have the appropriate centripetal acceleration

(this is geometry, not physics :wink:)

if the net force isn't enough to give you that acceleration (this is physics), you can't stay in the circle :smile:
 
Thanks for the help, man. But I guess I failed to explain my question clearly. I am saying that if the velocity decreases so much that, at the top of the loop, the weight becomes greater than the 'required centripetal force', the person on the roller coaster is going to fall head-on vertically downwards.
Centripetal force at the top of the loop = weight + contact force
If velocity decreases and keeps decreasing, the centripetal force also decreases, and the contact force decreases until it becomes zero. If the velocity doesn't decrease any further, the coaster will 'just' make the loop. But if it does, then it's supposed to fall downwards. I just don't understand why?
 
hi shahir_elmadr! :smile:
shahir_elmadr said:
… if the velocity decreases so much that, at the top of the loop, the weight becomes greater than the 'required centripetal force', the person on the roller coaster is going to fall head-on vertically downwards.

no, he'll follow a parabola just like any projectile …

he'll leave the rails at the angle at which the reaction force is zero, and gracefully follow a parabola until he crashes into the opposite side of the loop :wink:

(and if he actually reaches the top, he'll stay on even if the reaction force there is zero)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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