Falling object and air resistance

Click For Summary

Homework Help Overview

The discussion revolves around the dynamics of a falling object considering the effects of air resistance. The original poster presents a mathematical expression for the height of a falling object and poses questions regarding its simplification and the derivation of velocity and acceleration.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to simplify the given expression for short times and what "reduces" means in this context. Some participants suggest using a power series expansion for the exponential term to facilitate this simplification.
  • There are inquiries about finding the velocity and acceleration from the height equation, with one participant noting the differentiation process involved.

Discussion Status

Participants are actively engaging with the mathematical aspects of the problem, exploring the use of power series and differentiation. Guidance has been offered regarding the expansion of the exponential function and the differentiation process, but there is no explicit consensus on the approach to take.

Contextual Notes

The original poster's attempt is constrained by a lack of familiarity with power series and differentiation techniques, which are crucial for progressing in the problem. There is also a mention of external resources for further reference.

justin016
Messages
2
Reaction score
0

Homework Statement



the effect of air resistance is to slow down a moving object. It can be shown that height of a falling object is given by the following

Homework Equations



y=y0-[t+(e^-bt - 1)/b]g/b

a. show that for short times this reduces to the expected expression
y=y0-1/2gt^2

b. Find the velocity
c. Find the acceleration

The Attempt at a Solution



I really not sure where to start with part a. what does it mean by reduces?
 
Physics news on Phys.org
You must replace the exponential with its power series. The power series will be a constant term plus a term with t, plus a t^2 term, plus a t^3 term and so on. For small times you can ignore the higher power terms. In this case keep only the first 3 terms.
If you aren't familiar with power series, you can look them up in the back of the book or in a reference book with tables of integrals. The exponential one is also given here:
http://en.wikipedia.org/wiki/Power_series
 
Delphi51 said:
You must replace the exponential with its power series. The power series will be a constant term plus a term with t, plus a t^2 term, plus a t^3 term and so on. For small times you can ignore the higher power terms. In this case keep only the first 3 terms.
If you aren't familiar with power series, you can look them up in the back of the book or in a reference book with tables of integrals. The exponential one is also given here:
http://en.wikipedia.org/wiki/Power_series

Could you help explain how to find the velocity and the acceleration for the above equation. I know you differentiate it once for the velocity and then differentiate the velocity for the acceleration, but I'm having trouble.
 
The expression for y is pretty ugly; I would expand it out like this:
justin016.jpg

Go ahead and try to find dy/dt. I'm sure you can do the constant terms and the one with a t factor. For the exponential, recall that the derivative of e^x is e^x.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
13
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K