After performing a quadratic curve fit tool in Pro Logger, I was given the values: A = -1.426E-05 +/- 2.386E-06 , B = 0.02193 +/- 0.001581, C = 0.4785 +/- 0.1905.
With this information, how is “g” for Planet X determined from the parameters of the curve fit equation? And what is the value of “g” that you determined for Planet X?
y = At^2+Bt+C or y = at^2/2 + v0t + y0
y = 1/2gt^2 or g =2y/t^2
The Attempt at a Solution
My first thought is that since there was no initial velocity and no initial position given, I am focusing in on y = at^2/2 or the y = 1/2gt^2.
Since the seconds equation has the most obvious means to find "g", that is what I have tried with no success.
Example: 168 = 1/2(g)(4.00)^2 --> I am resulting with a 'g' value of 21
While for: 107 = 1/2(g)(3.00)2 --> I come up with a 'g' value of 23.8
Am I using an incorrect method of finding the value of "g"? Any help would be most appreciated.