Falling rocket payload problem

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SUMMARY

The discussion focuses on calculating the time it takes for a rocket payload to fall from an altitude of 260 km to 160 km, considering the variation of gravity from 9.3 m/s² to 9.0 m/s². The equation used is G*Me / (r(t)²) = r''(t), where G is the gravitational constant and Me is the mass of Earth. The user attempts to apply Laplace transforms but encounters difficulties in the algebraic manipulation of the equation. A suggested solution involves using the relationship r'' = dv/dt = (dv/dr)(dr/dt) and the conservation of energy principle.

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Homework Statement


Say I've got a rocket payload (there's no thrust, it's just dead weight) falling to Earth from an altitude of 260km and I want to calculate the time it takes it to fall to 160km. It's far enough away from Earth that I can't make the assumption that gravity is constant (it varies from 9.3 m s^-2 to 9.0 m s^-2). I am making the assumption that there is no drag.


Homework Equations



I've been trying to solve the following:

G*Me / ( r(t)^2 ) = r''(t)

where G is the gravitational constant, Me is the mass of earth, r(t) is the distance from the payload to earth, and r''(t) is the acceleration.


The Attempt at a Solution



I've been trying to use laplace transforms to solve the equation but I'm a bit rusty.

I moved the r(t) ^2 over:

G*Me = r''(t) * r(t)^2

then I took the laplace transform (I'm pretty sure this is where I messed up)

G*Me/s = (s^2 R(S) - s r(0)) *R(s)^2

then I did some more algebra:

G*Me = s^3 R(s) ^3 - s^2 r(0)

and I'm not really sure where to go from here. Please help!
 
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hi sovtek! welcome to pf!

(try using the X2 icon just above the Reply box :wink:)
sovtek said:
G*Me = r''(t) * r(t)^2

use the standard trick: r'' = dv/dt = dv/dr dr/dt = vdv/dr :wink:

(or just use conservation of energy, with potential energy = -GMe/r)
 

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