Faraday's Law help, not sure if I'm using the equations correctly.

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SUMMARY

The discussion centers on the application of Faraday's Law in calculating the electromotive force (ε) generated by a coil in a time-varying magnetic field. The coil has a radius of 3.55 cm and contains 480 turns, while the magnetic field is defined by the equation B = (1.20e-2 T/S)t + (3.05e-5 T/s^{4})t^{4}. The correct approach involves differentiating the magnetic flux (Φ_B) with respect to time, leading to the conclusion that ε = -dΦ_B/dt, rather than ε = -Φ_B/t. A crucial step is recognizing the need to multiply the second term by 4 when differentiating t^4, which resolves the initial calculation error.

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Homework Statement



A coil 3.55 cm radius, containing 480 turns, is placed in a uniform magnetic field that varies with time according to B = (1.20e-2 T/S)t + (3.05e-5 T/s^{4} )t^{4}. The coil is connected to a 620 Ohm resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil.

Homework Equations



\Phi_{B}=BA
ε = - \frac{\Phi_{B}}{t}

The Attempt at a Solution



First I divided by t and removed a t from each term in "B"

r = .0355
N = 480

A = \pi(.0355)^{2} = 3.959192142e-3
AN = (3.959192142e-3)(480) = 1.900412228

So all we're left with is:
BAN = 1.900412228 [(1.20e-2 T/S) + (3.05e-5 T/s^{3} )t^{4}]

ε = (2.28e-2 V) + (5.80e-5 V/s^{3})t^{3} should be my final answer but mastering physics says I'm wrong. Please help thanks!

EDIT:

I just found a posting where they multiplied the second term in B (3.05e-5 T/s^{3} )t^{4} by 4. When I did that I got the correct answer! But I don't know why I would multiply the term by 4. Any thoughts?
 
Last edited:
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I have not checked all of your maths but did you remember to x4 when you differentiated t^4 ??
 
beanus said:
ε = - \frac{\Phi_{B}}{t}
ε = -\frac{d \Phi_{B}}{dt}, \ \text{ not } \ - \frac{\Phi_{B}}{t}
 

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