Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Fe needed to lift up mass of size m

  1. May 25, 2015 #1
    opposites magnetic fields repel each others. How big of an magnetic would I need to lift mass ( 5g) 3 centimetre in the air.
    F = MA
    A = 9.81 m/s^2
    M = mass of the object ( 5 g)
    F = 49.05

    F = I L x B
    49.05 = IL X B
    I = 3000 mA ( from a AA battery)
    µ = 4π E-7 T m/A
    Bsol = µ N/L I
    F = IL X µ N/ L * I
    N= number of turns in coil

    N = 10
    L = 10 m
    um..
    Am I doing this right? I feel like I am missing something...
     
  2. jcsd
  3. May 25, 2015 #2
    Mass of object must be kilogram.
     
  4. May 25, 2015 #3

    davenn

    User Avatar
    Science Advisor
    Gold Member

    no opposite poles attract :wink:


    an AA battery is going to struggle to give 3A for any length of time ( other than some of your high current NiCd's)



    don't really know, you showed a lot of formula without plugging in the numbers and showing your working


    Dave
     
  5. May 27, 2015 #4
    in Fb = IL X B
    what unit should L be in ?
    meters?

    if F = 49.05 N that mean that you need Fb to be greater than 49.05 to get the object off the ground right?
    but how do you get how high up it will go ?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Fe needed to lift up mass of size m
Loading...