Fe needed to lift up mass of size m

[btb4198]

opposites magnetic fields repel each others. How big of an magnetic would I need to lift mass ( 5g) 3 centimetre in the air.
F = MA
A = 9.81 m/s^2
M = mass of the object ( 5 g)
F = 49.05

F = I L x B
49.05 = IL X B
I = 3000 mA ( from a AA battery)
µ = 4π E-7 T m/A
Bsol = µ N/L I
F = IL X µ N/ L * I
N= number of turns in coil

N = 10
L = 10 m
um..
Am I doing this right? I feel like I am missing something...

 

[Quarlep]

Mass of object must be kilogram.

 

[davenn]

opposites magnetic fields repel each others.

no opposite poles attract

I = 3000 mA ( from a AA battery)

an AA battery is going to struggle to give 3A for any length of time ( other than some of your high current NiCd's)

um..
Am I doing this right? I feel like I am missing something...

don't really know, you showed a lot of formula without plugging in the numbers and showing your workingDave

 

[btb4198]

in Fb = IL X B
what unit should L be in ?
meters?

if F = 49.05 N that mean that you need Fb to be greater than 49.05 to get the object off the ground right?
but how do you get how high up it will go ?