Interpretation of a before $\gamma^{5}$ in J$_{\alpha}$

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The discussion centers on the interpretation of the factor "a" before γ^5 in the current J_α, specifically in the context of muon decay calculations. Participants express concern that this additional factor complicates the standard form of the current, which typically features only (1 - γ^5). The relative strength of the axial current is highlighted, noting that it is unity for leptons. The conversation reveals challenges faced in calculating the muon decay rate using this modified current form. Overall, the complexities introduced by the factor "a" are acknowledged as potentially problematic for accurate decay rate computations.
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Could you explain what's the interpretation of a before \gamma^{5} in this current:

J_{\alpha}=\bar{\psi_{e}}\gamma^{\alpha}\left(1-a\gamma^{5}\right)\psi_{\nu_{e}} +\bar{\psi_{\mu}}\gamma^{\alpha}\left(1-a\gamma^{5}\right)\psi_{\nu_{\mu}}?

And will this factor complicate calculations of decay rate of muon very much? I've seen that the standard form of current in the most popular books contains just 1-\gamma^{5}.
 
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It is the relative strength of the axial current. It's unity for leptons. But where did you get this? It's a poor way to write this, since it's the vector current that changes.
 
Vanadium 50 said:
But where did you get this? It's a poor way to write this, since it's the vector current that changes.
It's a task from my studies. I have to calculate the decay rate for muon starting from hamiltonian with current in this form. I've started and ran into troubles.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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