Is it possible to express fermion annihilation operator as a function of position and momentum?(adsbygoogle = window.adsbygoogle || []).push({});

I've seen on Wikipedia the formula for boson annihilation operator:

[tex]

\begin{matrix} a &=& \sqrt{m\omega \over 2\hbar} \left(x + {i \over m \omega} p \right) \\ a^{\dagger} &=& \sqrt{m \omega \over 2\hbar} \left( x - {i \over m \omega} p \right) \end{matrix}

[/tex]

But what about fermions? Is it possible to get anticommutation relations from canonical relations alone, or is it necessary to postulate something else?

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# Fermion annihilation operators from position and momentum

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