Field momentum inside a parallel plate capacitor

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SUMMARY

The discussion centers on the concept of field momentum within a parallel plate capacitor, where the top plate has a charge density of sigma and the bottom plate has a charge density of -sigma. According to Griffiths' textbook, the momentum is proportional to the Poynting vector (E x B), which indicates that without a magnetic field, the field momentum is zero. However, the inquiry raises the possibility of a net flow of field momentum into the cubic volume Omega, suggesting that the situation may be more complex than initially understood, particularly since the volume does not include the negative plate.

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  • Understanding of electric fields and charge density in capacitors
  • Familiarity with the Poynting vector and its implications in electromagnetism
  • Knowledge of the principles of field momentum in electromagnetic theory
  • Basic concepts of parallel plate capacitors and their configurations
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  • Study the derivation and implications of the Poynting vector in static electric fields
  • Explore the concept of field momentum in electromagnetic systems
  • Investigate scenarios involving dielectric materials and their effects on electric fields
  • Examine the role of boundary conditions in electromagnetic field calculations
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Students and professionals in physics, particularly those focusing on electromagnetism, electrical engineers, and anyone studying the dynamics of electric fields in capacitive systems.

brian0918
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The system is a parallel plate capacitor, top plate has charge density sigma, bottom play has charge density -sigma. I'm looking for the "field momentum" inside the cubic volume Omega shown in the picture.

My book (Griffiths) is a little unclear on exactly what this is, and seems to be saying that the momentum is proportional to the Poynting vector ExB, so since there doesn't seem to be a magnetic field, this would suggest the field momentum is zero.

Is this correct?


The only problem I'm having is that, later in the problem, it asks if there's a net flow of field momentum into the cube, so I'm thinking there's more to the problem than what I'm seeing. Could anyone help clear this up?


Thanks.
 

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Unless you have current flowing through the dielectric or it's part of an AC circuit you won't have a magnetic field. Is there any other information provided?
 
There's no other information. So the field momentum is indeed zero?

What about a net flow of the field momentum into the cubic volume Omega?
 
brian0918 said:
There's no other information. So the field momentum is indeed zero?

What about a net flow of the field momentum into the cubic volume Omega?

That would imply an infinite buildup of momentum/energy over time not to mention there is no source for that.
 
Are you sure about the net flow into volume Omega being zero? If you look at the picture, the volume doesn't include the negative plate, just the positive plate. Does this change anything? The book doesn't explain this at all.
 

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