This discussion focuses on calculating the magnetic field outside a finite solenoid, particularly perpendicular to its axis. Participants emphasize the use of Ampere's law and the Biot-Savart law for deriving the magnetic field equations. The magnetic field can be approximated by treating the solenoid as a series of current loops, and the relevant equations can be found in "Classical Electrodynamics" by Jackson and "Classical Electromagnetism" by Franklin. The introduction of water's effects on the magnetic field remains unexplored in this discussion.
PREREQUISITESStudents and professionals in physics, electrical engineering, and anyone interested in the behavior of magnetic fields around finite solenoids and their interactions with materials like water.
You just have to use Ampere's law and add the field of all the loops in the solenoid. For a short solenoid, you can approximate with a single loop with total current = NI where N is the number of turns. But you can see that it is similar to the field some distance from two parallel wires with currents in opposite directions (ie at a distance d>>s where s is the separation between the wires) which is effectively 0 because the fields cancel.bjornmag said:I can`t seem to find any information on how to calculate the magnetic field outside a real finite solenoid. I do not need the field on-axis, but rather perpendicular to the solenoid.