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Introductory Physics Homework Help
Figuring out changes in Intensity (Inverse Square Law)
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[QUOTE="gneill, post: 4973525, member: 293536"] Intensity follows an inverse square law with distance. So you'd expect the intensity at 3R to be 9 times [I]less[/I] than the intensity at R, right? So the inverse square law for intensity vs distance looks like: $$\frac{I_2}{I_1} = \frac{R_1^2}{R_2^2}$$ Decibels are a comparison of intensities, so if you want to use the distances in the decibel formula rather than the intensities you need to remember to keep the inverse square law in mind and employ the squares of the distances and the "inverse" property as well. That said, take a look at the ratio above and then your Relevant equation. Does your equation preserve the "inverse" and "square" properties? [/QUOTE]
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Figuring out changes in Intensity (Inverse Square Law)
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