Figuring Out Displacement Vector Direction

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SUMMARY

The discussion focuses on determining the direction of a velocity vector based on a given displacement vector from point P to point Q, represented as 2i + 5j + 3k. The magnitude of the velocity vector is established at 5 cm/sec. The correct approach involves calculating the unit vector of the displacement and scaling it by the velocity magnitude, resulting in v = 5(2/sqrt(38)i + 5/sqrt(38)j + 3/sqrt(38)k). The next step involves parameterizing the motion of the particle over time.

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  • Knowledge of unit vectors and their calculation
  • Familiarity with the concept of velocity in physics
  • Basic principles of parameterization in motion
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  • Explore the concept of parameterization in physics
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LeakyFrog
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There is an attached image I couldn't figure out how to make it in the post.

The attempt at a solution
a)
So I know that the direction of the velocity vector will be in the direction on the displacement vector from P to Q:

2i+5j+3k

I also know that the magnitude of the velocity vector is 5cm/sec.

My thought on this is that we find the unit vector in the direction of the displacement and then multiply it by 5. So we get:

v = 5(2/sqrt(38)i+5/sqrt(38)j+3/sqrt(38)k)

Is this thinking correct?
 

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for a) yes, now for b)think about pramterising the line along which the particle moves in terms of time
 

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