Figuring out the frequency of light using a solar cell

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SUMMARY

This discussion focuses on determining the frequency of light using a solar cell by applying energy concepts. The participant outlines the relationship between initial energy, work, and final energy using the equation E_i + W_n_c = E_f, where E_i represents initial energy, W_n_c denotes non-conservative work, and E_f is the final energy. The participant also discusses calculating power using the formula P = VI, while expressing concerns about measuring current directly. The conclusion emphasizes the necessity of using monochromatic light sources to accurately measure photon frequency, as power alone does not provide sufficient information about photon count.

PREREQUISITES
  • Understanding of energy concepts, specifically E_i + W_n_c = E_f
  • Familiarity with electrical power calculations (P = VI)
  • Knowledge of photon energy (E = hν)
  • Basic circuit theory, including voltage, current, and resistance relationships
NEXT STEPS
  • Research the use of monochromatic light sources for experiments
  • Learn about measuring current without damaging components
  • Explore advanced concepts in quantum mechanics related to photon behavior
  • Investigate methods for determining photon count in solar cell experiments
USEFUL FOR

Physics students, experimental researchers, and anyone interested in the practical applications of solar cells and light frequency measurement.

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Hey people,

I wanted to try this experiment. My experiment is to shine a light on a solar cell and try to figure out the frequency of the light. I do have some idea on how to do this using energy concepts.

E_i+W_n_c=E_f

E_i= initial energy in the system (joules)

W_n_c= work that isn't conservative (joules)

E_f= final energy in the system (joules)

I know that when electricity is passing through a wire it has a voltage and a current. Multiply those two together and you get power. However I can't measure amps directly because doing so will fry the circuit and in particular the solar cell. Current is equal to voltage over the resistance of the circuit so I can substitute that in for amps and still find the power. Multiply by the amount of time to pass and you get watts. I'll show it mathematically below.

VI=P

\frac{V}{R}=I

\frac{V^2}{R}=P

\frac{V^2t}{R}=W

I know this will be the final energy so it goes on the right side of the equation.

E_i+W_n_c=\frac{V^2t}{R}

Now the initial energy comes from the light source itself which is represented by

h\nu=W

so I plug it in.

h\nu+W_n_c=\frac{V^2t}{R}

However I don't think this equation is complete. I feel that I might be missing something. Can someone help me out?

Thanks! :smile:
 
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The only way this experiment could work would be if you were able to use perfectly monochromatic sources with exactly the same intensity.
The problem here is that whereas it is true the energy of a single photon is hf that doesn't tell you anything about how MANY photons are hitting the cell per second; i.e. there is no way to determine the frequency by just measuring the power generated by the cell.
 

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