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Hey people,
I wanted to try this experiment. My experiment is to shine a light on a solar cell and try to figure out the frequency of the light. I do have some idea on how to do this using energy concepts.
[tex]E_i+W_n_c=E_f[/tex]
[tex]E_i[/tex]= initial energy in the system (joules)
[tex]W_n_c[/tex]= work that isn't conservative (joules)
[tex]E_f[/tex]= final energy in the system (joules)
I know that when electricity is passing through a wire it has a voltage and a current. Multiply those two together and you get power. However I can't measure amps directly because doing so will fry the circuit and in particular the solar cell. Current is equal to voltage over the resistance of the circuit so I can substitute that in for amps and still find the power. Multiply by the amount of time to pass and you get watts. I'll show it mathematically below.
[tex]VI=P[/tex]
[tex]\frac{V}{R}=I[/tex]
[tex]\frac{V^2}{R}=P[/tex]
[tex]\frac{V^2t}{R}=W[/tex]
I know this will be the final energy so it goes on the right side of the equation.
[tex]E_i+W_n_c=\frac{V^2t}{R}[/tex]
Now the initial energy comes from the light source itself which is represented by
[tex]h\nu=W[/tex]
so I plug it in.
[tex]h\nu+W_n_c=\frac{V^2t}{R}[/tex]
However I don't think this equation is complete. I feel that I might be missing something. Can someone help me out?
Thanks!
I wanted to try this experiment. My experiment is to shine a light on a solar cell and try to figure out the frequency of the light. I do have some idea on how to do this using energy concepts.
[tex]E_i+W_n_c=E_f[/tex]
[tex]E_i[/tex]= initial energy in the system (joules)
[tex]W_n_c[/tex]= work that isn't conservative (joules)
[tex]E_f[/tex]= final energy in the system (joules)
I know that when electricity is passing through a wire it has a voltage and a current. Multiply those two together and you get power. However I can't measure amps directly because doing so will fry the circuit and in particular the solar cell. Current is equal to voltage over the resistance of the circuit so I can substitute that in for amps and still find the power. Multiply by the amount of time to pass and you get watts. I'll show it mathematically below.
[tex]VI=P[/tex]
[tex]\frac{V}{R}=I[/tex]
[tex]\frac{V^2}{R}=P[/tex]
[tex]\frac{V^2t}{R}=W[/tex]
I know this will be the final energy so it goes on the right side of the equation.
[tex]E_i+W_n_c=\frac{V^2t}{R}[/tex]
Now the initial energy comes from the light source itself which is represented by
[tex]h\nu=W[/tex]
so I plug it in.
[tex]h\nu+W_n_c=\frac{V^2t}{R}[/tex]
However I don't think this equation is complete. I feel that I might be missing something. Can someone help me out?
Thanks!