Final Speed of an Electron with 22kv Potential Difference?

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SUMMARY

The final speed of an electron accelerated through a potential difference (p.d.) of 22 kV can be calculated using the work-energy principle. The work done on the electron is equal to the change in kinetic energy, which is determined by the equation: Work done = p.d. x Charge of the electron. Given the charge of the electron as approximately 1.6 x 10^-19 coulombs, the work done is calculated as 3.25 x 10^-15 joules, leading to a final speed of approximately 2.65 x 10^7 m/s.

PREREQUISITES
  • Understanding of basic physics concepts such as kinetic energy and potential difference.
  • Familiarity with the equation for work done (Work = Voltage x Charge).
  • Knowledge of the charge of an electron (1.6 x 10^-19 coulombs).
  • Ability to manipulate equations to solve for final speed using kinetic energy formulas.
NEXT STEPS
  • Study the work-energy theorem in classical mechanics.
  • Learn about electric potential and its relationship to kinetic energy.
  • Explore the concept of electron acceleration in electric fields.
  • Investigate the effects of potential difference on particle motion in physics.
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Students studying physics, particularly those focusing on electromagnetism and particle dynamics, as well as educators seeking to explain the relationship between electric potential and kinetic energy.

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Homework Statement



Assuming the electron starts from rest, what will be the final speed reached by the electron?

We have p.d. of 22kv, and the 'work done on the electron', worked out previously as 3.25^-15


Homework Equations



*shrug* I swear we have never covered this before

The Attempt at a Solution



No idea how to even begin
 
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The work done by the p.d.=Change in kinetic energy of the electron

Work done = p.d. x Charge of the electron
 
*facepalm* I should have known that.

Thanks rock.freak!
 

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