Final Temp of Water & Zinc: Find the Answer

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Homework Help Overview

The problem involves a thermal equilibrium scenario where a piece of zinc is placed in water, and participants are tasked with finding the final temperature of both substances. The context includes specific heat capacities and initial temperatures of the materials involved.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of energy principle and its application to the problem. There is an attempt to set up an equation based on heat transfer between the zinc and water. Some participants question the correctness of their calculations and the final temperature.

Discussion Status

The discussion is ongoing, with participants exploring the setup of the energy balance equation. Some guidance has been provided regarding the concept of thermal equilibrium, but no consensus has been reached on the final temperature.

Contextual Notes

Participants are working under the assumption that the system is insulated and that no heat is lost to the surroundings. There is a focus on ensuring the correct application of specific heat capacities in their calculations.

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Homework Statement



A 10 kg piece of zinc at 68◦C is placed in a container of water. The water had a mass of 32 kg and a temperature of 14◦C before the zinc was added. The specific heat of zinc and water are 388 J/kg ·◦C and 4180 J/kg ·◦C. What is the final temperature of water and zinc? Answer in units of ◦ C.

Homework Equations



How do you do this? What formula do I use? TIA
 
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Think about the law of energy conservation. If you assume that the system is insulated from the surroundings, then any heat transferred from the water will be absorbed by the zinc. i.e.:

Energy gained by water = energy lost by zinc

You also know that two objects in contact will eventually reach thermal equilibrium, so that their final temperatures are the same. What final temperature, T, will make the energy transferred by the water and zinc equal?
 
So is it 41 C?
 
mZnCZn(Tf-TZn i) + mH2OCH2O(Tf-TH2O i)=0

When I plug in my numbers:

(10 kg)(388 J/kg C)(Tf-68 C) + (32 kg)(4180 J/kg C)(Tf- 14 C) = 0
3880 J/C (Tf-68 C) + 133760 J/C (Tf- 14 C) = 0

Than?!
 

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