Final Temperature of Copper-Water System

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Discussion Overview

The discussion revolves around calculating the final temperature of a copper-water system after the copper is placed in water. It involves concepts of heat transfer, specifically the heat lost by the copper and the heat gained by the water and the vessel. The context is primarily homework-related, focusing on the application of thermal equilibrium principles.

Discussion Character

  • Homework-related, Mathematical reasoning, Technical explanation

Main Points Raised

  • One participant expresses uncertainty about how to approach the problem of finding the final temperature.
  • Another participant states that heat lost by the copper must equal the heat gained by the water and the vessel.
  • A question is raised regarding how to account for the two separate systems (copper and water) when combining them.
  • It is suggested to treat the heat gained and lost separately, using the provided equations for each mass, with the final temperature being the common variable.
  • A participant inquires about how to incorporate the heat capacity of the vessel into the calculations.
  • Another response indicates that the heat capacity of the vessel can be combined with that of the water, suggesting that the specifics of mass and specific heat may not significantly impact the overall approach.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method to incorporate the heat capacity of the vessel or how to handle the two separate systems, indicating that multiple competing views remain on these aspects.

Contextual Notes

There are limitations regarding the assumptions made about the system, such as the treatment of the vessel's heat capacity and the specifics of combining the two different masses. The discussion does not resolve these points.

grapejellypie
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Homework Statement


A 505g piece of copper tubing is heated to 99.9 degrees C and placed in an insulated vessel containing 59.8g of water at 24.8 degrees C. Assuming no loss of water and a heat capacity for the vessel of 10.0 J/K, what is the final temperature of the system? (c of coppuer is 0.387 J/(gk))


Homework Equations



q = c x mass x change in temperature
change in termperature = T[final] - T[initial]

The Attempt at a Solution


I have no idea how to go about solving this problem
 
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Heat lost = heat gained.
 
how do you account for the two separate systems combining into one?
(i.e. how would you deal with the two different masses?)
 
Treat heat gained/lost separately. Use equation you have already posted for each mass separately. The only commong thing in both equations will be the final temperature, and that's what you will solve for.
 
how do you incorporate the heat capacity of the vessel?
 
Combine it with water (simply add them, nothing more fancy). It coul be given as vessel mass and specific heat, but the heat capacity is the same, just details are hidden - which completely doesn't matter.
 

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