Final Velocity Calculation for Inelastic Collision of Freight Trains

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SUMMARY

The final velocity calculation for the inelastic collision of two freight trains involves using the conservation of momentum principle. Engine 1, with a mass of 1.4x104 kg traveling at 45 km/h [N] and Engine 2, with a mass of 1.5x104 kg traveling at 53 km/h [W], requires the correct application of momentum equations. The initial momentum must be calculated and then divided by the total mass of both engines to find the final velocity. The correct final velocity is 9.7 m/s, achieved by properly accounting for both masses in the calculation.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Knowledge of vector addition for velocity components
  • Familiarity with unit conversions (e.g., km/h to m/s)
  • Basic algebra for solving equations
NEXT STEPS
  • Study the conservation of momentum in inelastic collisions
  • Learn about vector decomposition for velocity calculations
  • Practice unit conversion techniques, specifically from km/h to m/s
  • Explore examples of inelastic collisions in physics problems
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Physics students, educators, and anyone interested in understanding the principles of momentum and collision dynamics in mechanics.

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Homework Statement


Two freight trains have a completely inelastic collision at a track crossing. Engine 1 has a mass of 1.4x10^4 kg and is initially traveling at 45 km/h [N].
Engine 2 has a mass of 1.5x10^4 kg and is initially traveling at 53 km/h [W]. Calculate the final velocity.

Homework Equations

The Attempt at a Solution


p^2=p1^2+ p2^2
=(1.4x10^4)(12.5m/s)^2+ (1.5x10^4)(14.72m/s)^2
=281740m/s

The answer in the textbook is 9.7m/s. What am I doing wrong?
 
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I just realized my mistake, i forgot to divide it by both mass
 

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