Finally, discuss some physical limitations that might

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The discussion revolves around the physical limitations of an LRC circuit in relation to its oscillating behavior. Participants question whether the clock can run indefinitely and if the current remains constant or becomes harder to detect over time. It is noted that while theoretically the clock could run forever, practical limitations exist, such as the inability to have a resistance (R) of zero in real life. Additionally, the values of resistance (R), capacitance (C), and inductance (L) can change over time and environmental conditions, impacting the circuit's performance. The conversation highlights the complexities of maintaining a consistent frequency in oscillating systems.
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"Finally, discuss some physical limitations that might ..."

Homework Statement



Part (d) of problem 1 here: http://faculty.washington.edu/joelzy/402_502_W13_hw4.pdf

Homework Equations



I have (I(t) I'(t))T = cos(t/√(LC))k1 + sin(t/√(LC))k2, some k1, k2 ε ℂ2 for my solution and so I know that decreasing the value of LC increases the ticking frequency of this clock.

The Attempt at a Solution



But I'm at a loss for what to put for this "discuss some physical limitations" thing. Thoughts?
 
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For one thing - do you think this clock will run forever? Even if so, does the current level stay constant or does it get harder to detect over time? Do the values of R, C and L change in any way over time?
 


rude man said:
For one thing - do you think this clock will run forever?

Theoretically, yes.

Even if so, does the current level stay constant or does it get harder to detect over time?

Well, it oscillates, since current is V = RI, R is constant, I is oscillating.

Do the values of R, C and L change in any way over time?

I don't really know since I'm not an electrical engineer
 


I do not see any dependence of the solution on R. How come?
 


voko said:
I do not see any dependence of the solution on R. How come?

If we want it to tick with a constant frequency, then we want the node to be a center, so we want R=0. Right? We want I(t)=0 periodically.
 


Jamin2112 said:
Theoretically, yes.



Well, it oscillates, since current is V = RI, R is constant, I is oscillating.



I don't really know since I'm not an electrical engineer

Does it seem reasonale to assume that whatever circuit you use to detect the zero crossings of the current has a limitation as to how low the current can be before it can't tell the difference between that low level and zero?

And BTW you can't have R = 0 in real life. Besides, the problem specifies a resistor.

And FYI R, C and L do change over time & environment. That's why crystal oscillators are used in your PC!
 


Jamin2112 said:
If we want it to tick with a constant frequency, then we want the node to be a center, so we want R=0. Right? We want I(t)=0 periodically.

Do you think it is physically possible to have R = 0? The circuit is called LRC for a reason.
 


voko said:
Do you think it is physically possible to have R = 0? The circuit is called LRC for a reason.

Isn't my intuition right, though, that we want the vector field of (I I')T to be something circling the origin forever?
 


Is that possible with R > 0?
 
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