Find a normal vector to a unit sphere using cartesian coordinates

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To find a normal vector to a unit sphere centered at the origin using Cartesian coordinates, any direction can serve as a normal vector at some point on the surface. The unit sphere is defined by the equation x² + y² + z² = 1. An effective method is to consider an arbitrary point P(x, y, z) on the sphere and use the gradient of the function F(x, y, z) = x² + y² + z², which is always normal to level surfaces. The discussion emphasizes that clarity in the problem statement could improve understanding. Understanding the relationship between position vectors and normal vectors is crucial for solving this problem.
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Homework Statement


Consider a unit sphere centered at the origin. In terms of the Cartesian unit vectors i, j and k, find the unit normal vector on the surface

Homework Equations


A dot B = AB cos(theta)
A cross B = AB (normal vector) sin(theta)
Unit sphere radius = 1

The Attempt at a Solution


Isn't any direction a normal vector?
i x j = + k
j x i = - k
etc.
 
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Frozen Light said:

Homework Statement


Consider a unit sphere centered at the origin. In terms of the Cartesian unit vectors i, j and k, find the unit normal vector on the surface

Homework Equations


A dot B = AB cos(theta)
A cross B = AB (normal vector) sin(theta)
Unit sphere radius = 1

The Attempt at a Solution


Isn't any direction a normal vector?
i x j = + k
j x i = - k
etc.
Any nonzero vector would be a normal at some point on the surface of the sphere. My guess is that you should take an arbitrary point P(x, y, z) on the surface, and find the normal to it. If that's what is wanted in the problem, it could have been written more clearly.
 
Thank you, that would make a bit more sense.
 
The unit sphere is of the form x^2+ y^2+ z^2= 1. You can think of that as a 'Level Surface" of the function F(x, y, z)= x^2+ y^2+ z^2 and use the fact that the gradient of such a function, \nabla F, is always normal to level surfaces.
 
Or think about what direction a position vector to a point on the sphere has.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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