Find a unit normal to the plane containing a and b

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Homework Help Overview

The problem involves finding a unit normal vector to a plane defined by two points, a and b, given as vectors in three-dimensional space. The points are a=(3,-1,2) and b=(1,3,-2). There is some confusion regarding the definition of the plane and the method to find the normal vector.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of finding the unit normal vector, with one participant initially attempting to add the vectors a and b. Another participant questions the interpretation of the problem, noting that two points define a line rather than a unique plane.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the correct approach to finding the unit normal vector, and there is acknowledgment of a misunderstanding regarding the problem setup.

Contextual Notes

There is uncertainty about whether the origin is included in the plane defined by points a and b, which affects the interpretation of the problem. Participants are also discussing the correct format for entering mathematical expressions.

wolfspirit
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Homework Statement


Find a unit normal to the plane containing a and b. a=(3;-1; 2) and b=(1; 3;-2)

Homework Equations


\frac{V}{|V|} where V = a+b

The Attempt at a Solution


(3;-1; 2) +1; 3;-2)=(4,2,0)=V
|V| = \sqrt{4^2+2^} = 2\sqrt{5}

there fore the unit vector is (\frac{2}{\sqrt{5}} \widehat{i}, \frac{1}{\sqrt{5} \widehat{j} )

but this looks like a very messy answer i am therefore not convinced i have done it right, if some one could give me some guidance that would be very much appreciated :)
 
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ah ok i thought one could enter latex code here...
 
wolfspirit said:

Homework Statement


Find a unit normal to the plane containing a and b. a=(3;-1; 2) and b=(1; 3;-2)
What plane? Two points determine a line. There are an infinite number of planes containing a given line so an infinite number of planes containing two given points.

2. Homework Equations
\frac{V}{|V|} where V = a+b

The Attempt at a Solution


(3;-1; 2) +1; 3;-2)=(4,2,0)=V
|V| = \sqrt{4^2+2^} = 2\sqrt{5}

there fore the unit vector is (\frac{2}{\sqrt{5}} \widehat{i}, \frac{1}{\sqrt{5} \widehat{j} )

but this looks like a very messy answer i am therefore not convinced i have done it right, if some one could give me some guidance that would be very much appreciated :)
You have added the two given points. For one thing what do you mean by "adding points"? Or are you adding the position vectors of the two points? Are you given that the origin is also in this plane? But even in that case the sum of the two position vectors would be another vector in that same plane. Frankly, you seem to have completely misunderstood and misread this problem! Please reread it and then restate it here.
 
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wolfspirit said:
ah ok i thought one could enter latex code here...
You can- but you have to do it correctly!
1) Begin and end with [ tex ] and [ /tex ] (without the spaces) \int_0^\infty e^{-x^2}dx= \sqrt{\pi}
2) Begin and end with [ itex ] and [ /itex] in order to keep it "in line" (again without the spaces) \int_0^\infty e^{-x^2}dx= \sqrt{\pi}
3) Begin and end with "# #" (without the space) ##\int_0^\infty e^{-x^2}dx= \sqrt{\pi}##
 
HallsofIvy said:
You can- but you have to do it correctly!
1) Begin and end with [ tex ] and [ /tex ] (without the spaces)
∫∞0ex2dx=π√​
Just chipping in - you can also place a double dollar sign (i.e. $ ) before and after the content that you want to display in latex. (It won't appear in line if you use dollar sign, just like when you use [ tex] .)
 
Hi,
Thanks for that!

I was using the wrong equation, i should have used $$ \frac{a X b}{|aXB|} $$
 
wolfspirit said:
Hi,
Thanks for that!

I was using the wrong equation, i should have used $$ \frac{a X b}{|aXB|} $$
So presumably the task was to find a unit normal to the plane containing a, b and the origin.
 

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