Find a vector normal to the plane at (2,1,7)

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Homework Help Overview

This discussion revolves around finding a vector normal to a plane and a paraboloid at a specific point, (2,1,7). The subject area includes vector calculus and geometry related to planes and surfaces.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the nature of normal vectors to planes, questioning whether the normal is consistent across the entire plane. There is also consideration of the use of gradients in relation to the paraboloid.

Discussion Status

The discussion includes attempts to clarify the properties of normal vectors and their application to both the plane and the paraboloid. Some participants express uncertainty about the initial approach, while others suggest revisiting relevant concepts to find useful information.

Contextual Notes

Participants are navigating the specifics of the problem, including the definitions and properties of normal vectors in different contexts, as well as the implications of the given equations for the plane and paraboloid.

mharten1
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Homework Statement


This is a two part problem
A) Find a vector normal to the plane at (2,1,7)
B) Find a vector normal to the plane tangent to the paraboloid at (2,1,7)


Homework Equations



Plane: z = x + y +4
Paraboloid: z = x^2 +3y^2

The Attempt at a Solution


I'm not sure where to start. I know that a vector normal to the plane is <1,1,-1>, but that isn't at (2,1,7). Any help?
 
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A plane has the same normal everywhere, doesn't it?
 
Dick said:
A plane has the same normal everywhere, doesn't it?

That's what I thought at first. But it seems too easy to be the solution to both questions. I'm going to read over the section again and see if I can find anything that will be useful.
 
mharten1 said:
That's what I thought at first. But it seems too easy to be the solution to both questions. I'm going to read over the section again and see if I can find anything that will be useful.

It's not the solution to the second question. Think about using the gradient.
 
Dick said:
It's not the solution to the second question. Think about using the gradient.

I was able to solve it, thank you. :)
 

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