A hockey puck sliding on a frozen lake comes to rest after 238 m. If its initial velocity is 3.8 m/s what is its acceleration if it is assumed constant? Answer in units of m/s^2
How long is it in motion? What is its speed after traveling 180 m?
x=xo + vot +1/2at^2
The Attempt at a Solution
...v^2=(3.8)^2 + 2a (-238)
but i don't know the velocity, cause i don't have the time!
3.8 m/s * 1/238 m = time?
I find that I can't do anything without the time! I'm so lost and confused. PLEASE HELP.