Find all the critical points of the function

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SUMMARY

The discussion centers on finding the critical points of the function f(x) = x ln(x). The derivative f'(x) is calculated using the product rule, resulting in f'(x) = 1 + ln(x). To find critical points, the equation 1 + ln(x) = 0 is set, leading to ln(x) = -1. The solution involves exponentiating both sides to determine the value of x, which is e^(-1). This process clarifies the steps needed to solve for critical points effectively.

PREREQUISITES
  • Understanding of calculus, specifically differentiation and critical points
  • Familiarity with logarithmic functions and properties
  • Knowledge of the product rule in calculus
  • Ability to solve exponential equations
NEXT STEPS
  • Study the product rule in calculus for differentiating functions
  • Learn about the properties of logarithmic functions and their applications
  • Explore methods for finding critical points and analyzing function behavior
  • Practice solving exponential equations to reinforce understanding
USEFUL FOR

Students studying calculus, mathematics educators, and anyone looking to deepen their understanding of differentiation and critical point analysis in functions.

Dustobusto
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Homework Statement

f(x) = x ln(x)

The attempt at a solution

f'(x) = product rule, resulting in 1 + ln (x)

So by way of solving the problem, set 1 + ln (x) = 0

Now idealistically, find something in x that, when added to 1, equals zero.

Now here's a problem I have. How do I know when to keep searching for something in ln (x) and when to subtract one on both sides to make ln (x) = 1 ? And even when I get to that point, how to I move forward?
 
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Dustobusto said:
Homework Statement

f(x) = x ln(x)

The attempt at a solution

f'(x) = product rule, resulting in 1 + ln (x)

So by way of solving the problem, set 1 + ln (x) = 0

Now idealistically, find something in x that, when added to 1, equals zero.

Now here's a problem I have. How do I know when to keep searching for something in ln (x) and when to subtract one on both sides to make ln (x) = 1 ? And even when I get to that point, how to I move forward?

I'm not sure why you are so confused. You want to solve log(x)=(-1). Exponentiate both sides.
 
Dustobusto said:
Homework Statement

f(x) = x ln(x)

The attempt at a solution

f'(x) = product rule, resulting in 1 + ln (x)

So by way of solving the problem, set 1 + ln (x) = 0

Now idealistically, find something in x that, when added to 1, equals zero.

Now here's a problem I have. How do I know when to keep searching for something in ln (x) and when to subtract one on both sides to make ln (x) = 1 ? And even when I get to that point, how to I move forward?

Add -1 to both sides to get ln(x) = -1
Now solve for x.
 

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