Find All Values of a for Continuous Function f on Real Numbers

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SUMMARY

To determine all values of "a" for which the piecewise function f(x) is continuous on all real numbers, the function is defined as f(x) = x + 1 for x ≤ a and f(x) = x² for x > a. The continuity condition requires that the left-hand limit and right-hand limit at x = a are equal, specifically that lim (x → a⁻) f(x) = lim (x → a⁺) f(x) = f(a). This leads to the equation a + 1 = a², which can be solved to find the specific values of "a" that maintain continuity.

PREREQUISITES
  • Understanding of piecewise functions
  • Knowledge of limits and continuity in calculus
  • Familiarity with polynomial functions
  • Ability to solve quadratic equations
NEXT STEPS
  • Study the properties of piecewise functions in calculus
  • Learn about limits and their application in determining continuity
  • Practice solving quadratic equations using the quadratic formula
  • Explore graphical representations of continuous functions
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Students studying calculus, mathematics educators, and anyone interested in understanding the continuity of piecewise functions.

margbelladot
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How do you find all the values of "a" such that f is continuous on all real numbers?

Find all values of a such that f is continuous on [itex]\Re[/itex]

f(x)= x+1 if x[itex]\leq[/itex] a
x^2 if x>a


I tried solving but i do not even know where to start! Please help!
 
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We know (or you should know!) that x+1 and x^2 are continuous functions because they are polynomials. When you create a continuous piece-wise function, ##f(x)##, you want ##f(a)## to be continuous. This means ##\displaystyle \lim_{x \to a^-} f(a) = \lim_{x \to a^+} f(a) = f(a)##

You can think of it in lay man's terms as choosing values of a so that you can graph the function without lifting your pencil at ##f(a)##.
 

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