Find an annihilator of x^2 + 2x^5

  • Thread starter magnesium12
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In summary: I think I was just trying to show that (D3)(D6) would work as an annihilator. But yes, x3x6 would equal x18.
  • #1
magnesium12
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Homework Statement


Find an annihilator of x2+2x5.

Homework Equations


xnecx -----> [D-c]n+1

[Q1(D)Q2(D)] = b1(x) + b2(x)

The Attempt at a Solution


[/B]
x2 -----> D3

2x5-----> D6

x2 + 2x5 ------> (D3)(D6) = D18

The answer should be D6.
 
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  • #2
magnesium12 said:

Homework Statement


Find an annihilator of x2+2x5.

Homework Equations


xnecx -----> [D-c]n+1

[Q1(D)Q2(D)] = b1(x) + b2(x)

The Attempt at a Solution


[/B]
x2 -----> D3

2x5-----> D6

x2 + 2x5 ------> (D3)(D6) = D18

The answer should be D6.
Doesn't the D6 operator also annihilate x2?
 
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  • #3
Mark44 said:
Doesn't the D6 operator also annihilate x2?

I guess it does. So does that mean there can be multiple annihilators and they'll all work? Or should you always pick the least common multiple?
 
  • #4
magnesium12 said:

Homework Statement


Find an annihilator of x2+2x5.

Homework Equations


xnecx -----> [D-c]n+1

[Q1(D)Q2(D)] = b1(x) + b2(x)
What does the last line mean? It's not clear to me.

The Attempt at a Solution


[/B]
x2 -----> D3

2x5-----> D6

x2 + 2x5 ------> (D3)(D6) = D18

The answer should be D6.
Why are you multiplying the two annihilators?
 
  • #5
magnesium12 said:
(D3)(D6) = D18
Didn't notice this before -- is x3x6 = x18?
 
  • #6
magnesium12 said:
I guess it does. So does that mean there can be multiple annihilators and they'll all work? Or should you always pick the least common multiple?
Dn+1 annihilates xn and all lower powers of x. I don't see that this is related to the LCM in any way.
 
  • #7
Mark44 said:
Didn't notice this before -- is x3x6 = x18?
Heh...I didn't notice that either.
 

1. What is an annihilator?

An annihilator is an algebraic expression that, when multiplied with a given polynomial, results in a zero polynomial. In other words, it "annihilates" the given polynomial.

2. How do you find an annihilator of a polynomial?

To find an annihilator of a polynomial, you must first determine the highest power of the variable in the polynomial. Then, you can construct an annihilator using the form (x-a)^n, where a is a constant and n is the highest power of the variable in the polynomial.

3. Can you explain the process for finding an annihilator of x^2 + 2x^5?

First, we determine the highest power of the variable, which in this case is 5. Then, we construct the annihilator using the form (x-a)^n. In this case, a=0 and n=5, so the annihilator is (x-0)^5, or simply x^5.

4. Why is finding an annihilator important in mathematics?

An annihilator is important in mathematics because it allows us to solve differential equations and perform other complex mathematical operations. It also has applications in engineering, physics, and other scientific fields.

5. Are there any other methods for finding an annihilator?

Yes, there are other methods for finding an annihilator, such as using the method of undetermined coefficients or using the Laplace transform. However, the method of constructing an annihilator using the form (x-a)^n is the most commonly used and straightforward method.

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