(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find an equation of the tangent line to the graph of the function f defined by the following equation at the indicated point.

(x - y - 1)^{3}= x; (1, -1)

3. The attempt at a solution

x^{3}-y^{3}=1

3y^{2}(dy/dx)-3x^{2}=0

3y^{2}(dy/dx)=3x2^{2}

(dy/dx)=3y^{2}/3x^{2}

(dy/dx)=x^{2}/y^{2}

slope = (dy/dx) = 1

y-(-1)= 1(x-1)

y=x-2

thats wrong -.-

i tried making it dy/dx = x/y and still wrong.

where am i messing up? I'm pretty sure it has to do with the x at the end but i have no idea what to do with it!

We just learned derivatives so I'm still messing up with them.

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# Find an equation of the tangent line to the graph of the function f

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