- #1

A_Munk3y

- 72

- 0

## Homework Statement

Find an equation of the tangent line to the graph of the function f defined by the following equation at the indicated point.

(x - y - 1)

^{3}= x; (1, -1)

## The Attempt at a Solution

x

^{3}-y

^{3}=1

3y

^{2}(dy/dx)-3x

^{2}=0

3y

^{2}(dy/dx)=3x2

^{2}

(dy/dx)=3y

^{2}/3x

^{2}

(dy/dx)=x

^{2}/y

^{2}

slope = (dy/dx) = 1

y-(-1)= 1(x-1)

y=x-2

thats wrong -.-

i tried making it dy/dx = x/y and still wrong.

where am i messing up? I'm pretty sure it has to do with the x at the end but i have no idea what to do with it!

We just learned derivatives so I'm still messing up with them.