Find angle with pith ball and vertical wall

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A 10.0 g pith ball with a charge of 1.52 μC hangs from a thread next to a charged vertical wall with a surface charge density of 3.57 μC/m². The calculations involve determining the angle the thread makes with the vertical by using the equations for tension and gravitational force. Initial calculations yielded an incorrect angle due to the mass being in grams instead of kilograms. After correcting the mass conversion, the angle was recalculated to be 72.3 degrees. The discussion emphasizes the importance of unit consistency in physics calculations.
britt
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1. The Question:
A 10.0 g pith ball, carrying a charge of 1.52 μC hangs from a thread attached to a charged vertical wall carrying a surface charge density σ = 3.57 μC/m2. Find the angle that the thread makes with the vertical.



Homework Equations





3. My attempt:

Tcosθ=mg Tsinθ=F
Canceling tension (sinθ/cosθ)=tanθ=(F/mg)
F=mgtanθ
σ=2ε0E
E=σ/2ε0=201694.9153
F=EQ=(201694.9153)(1.52E-6)=0.3065762712

F/mg= 0.0031283293 = tanθ
tan-1(0.0031283293) = 0.17924

Is this the correct angle?
 
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britt said:
1. The Question:
A 10.0 g pith ball, carrying a charge of 1.52 μC hangs from a thread attached to a charged vertical wall carrying a surface charge density σ = 3.57 μC/m2. Find the angle that the thread makes with the vertical.



Homework Equations





3. My attempt:

Tcosθ=mg Tsinθ=F
Canceling tension (sinθ/cosθ)=tanθ=(F/mg)
F=mgtanθ
σ=2ε0E
E=σ/2ε0=201694.9153
F=EQ=(201694.9153)(1.52E-6)=0.3065762712

F/mg= 0.0031283293 = tanθ
tan-1(0.0031283293) = 0.17924

Is this the correct angle?


Check your calculation of F/mg. The resulting value looks too small. Did you perhaps forget to change grams into kg for the mass?
 
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what are you using for Fgrav? (check the mass units!)
 
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when i changed g to kg i got the angle to be 72.3
 
britt said:
when i changed g to kg i got the angle to be 72.3

Yup. That looks better :smile:
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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