Find angular accleration to find torque

Click For Summary
SUMMARY

The discussion focuses on calculating torque using the equation T = I * α, where T is torque, I is the moment of inertia, and α is angular acceleration. The user has a motor speed of 2500 revolutions per second, translating to an angular speed (ω) of 261.8 radians per second. It is clarified that if the angular speed is constant, the angular acceleration (α) is zero, indicating that torque calculations may not be necessary under these conditions.

PREREQUISITES
  • Understanding of torque and its relation to angular motion
  • Familiarity with the concepts of moment of inertia (I)
  • Knowledge of angular velocity (ω) and angular acceleration (α)
  • Basic grasp of rotational dynamics equations
NEXT STEPS
  • Research the implications of constant angular velocity on torque calculations
  • Explore the relationship between moment of inertia and torque in different scenarios
  • Learn about angular acceleration and its calculation in non-constant rotational motion
  • Study the principles of rotational dynamics and their applications in engineering
USEFUL FOR

Mechanical engineers, physics students, and anyone involved in rotational dynamics or torque calculations will benefit from this discussion.

pully89
Messages
1
Reaction score
0
Ok, I have a a motor, so I know the speed in rev/s. The motor is going to power a wheel, so I have a second moment of area?, (I), and I want to calculate the torque. I know I can do this by using T=I*[tex]\alpha[/tex]. The speed of the motor is 2500 revolutions per second. So [tex]\omega[/tex] is 2[tex]\pi[/tex]f, which is 261.8 radians per second, but from here I am confused on how to work out the angular acceleration, although I think that [tex]\alpha[/tex]=[tex]\Delta[/tex][tex]\omega[/tex]/[tex]\Delta[/tex]t, but I'm still not sure how to get alpha, can anyone help?
 
Last edited:
Physics news on Phys.org
welcome to pf!

hi pully89! welcome to pf! :smile:

(have an alpha: α and a delta: ∆ and a pi: π and a tau: τ and an omega: ω :wink:)

if ω (angular speed) is constant, then α (angular acceleration) is zero

the relevant equation balances the torque in with the torque out, and really has almost nothing to do with I (the mass moment of area, or moment of inertia) :wink:
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 17 ·
Replies
17
Views
1K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
26
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K