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Find angular accleration to find torque

  • Thread starter pully89
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Ok, I have a a motor, so I know the speed in rev/s. The motor is going to power a wheel, so I have a second moment of area?, (I), and I want to calculate the torque. I know I can do this by using T=I*[tex]\alpha[/tex]. The speed of the motor is 2500 revolutions per second. So [tex]\omega[/tex] is 2[tex]\pi[/tex]f, which is 261.8 radians per second, but from here I am confused on how to work out the angular acceleration, although I think that [tex]\alpha[/tex]=[tex]\Delta[/tex][tex]\omega[/tex]/[tex]\Delta[/tex]t, but I'm still not sure how to get alpha, can anyone help?
 
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Answers and Replies

  • #2
tiny-tim
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welcome to pf!

hi pully89! welcome to pf! :smile:

(have an alpha: α and a delta: ∆ and a pi: π and a tau: τ and an omega: ω :wink:)

if ω (angular speed) is constant, then α (angular acceleration) is zero

the relevant equation balances the torque in with the torque out, and really has almost nothing to do with I (the mass moment of area, or moment of inertia) :wink:
 

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