MHB Find Area of A Rectangle With Shortcut

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To find the area of a rectangle with a perimeter of 72 cm, additional information about the rectangle's dimensions is required, as multiple rectangles can share the same perimeter. By defining the height as a variable, the base can be expressed as the difference from half the perimeter, leading to the area formula A = (36 - h)h. The maximum area occurs when the rectangle is a square, yielding an upper limit of 324 cm². The semi-perimeter of 36 cm is crucial for determining the relationship between the base and height. Understanding these concepts allows for a straightforward calculation of the area based on the chosen dimensions.
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hi all...

how do you find area of a rectangle, if its perimeter of a rectangle is = 72 cm?

i mean how to easy find it without hard work.

do you have a formula or just tricks similar like..

http://calculus-geometry.hubpages.com/hub/How-to-Find-the-Area-Perimeter-and-Diagonal-of-a-Rectangle

thanks in advance...

susanto
 
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For a given perimeter, there are an infinite number of rectangles that will have that perimeter. We need more information about the rectangle.
 
MarkFL said:
For a given perimeter, there are an infinite number of rectangles that will have that perimeter. We need more information about the rectangle.

if perimeter of a rectangle is = 72 cm, counting area of a rectangle =...

i need simple formula to calculate it.
possible?
 
Well, suppose we let the height $0<h<36$ be a free variable, then the base $b$ is $b=36-h$. Thus the area $A$ is:

$$A=bh=(36-h)h$$

Thus we find:

$$0<A\le324$$
 
The sum of the base and the height must be equal to the semi-perimeter, which is 36...half of 72. And the maximum area comes from the base and height being equal. So the upper bound is $18^2=324$.
 
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