Find area of regions bounded by curve and line

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SUMMARY

The discussion focuses on finding the area of regions bounded by the circle defined by the equation x² + y² = 9, the line y = 2x, and the x-axis in the first quadrant. The initial attempt involved transforming to polar coordinates with limits 0≤θ≤tan⁻¹(3) and 0≤r≤3, leading to an incorrect final answer of (9/2)tan⁻¹(3). The correct limits for θ should be 0≤θ≤cos⁻¹(1/√5), which corresponds to θ = tan⁻¹(2), resulting in the accurate area calculation of (9/2)tan⁻¹(2).

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Homework Statement
Find area of regions bounded by
x^2 + y^2 = 9, y = 2x, x-axis in the first quadrant

The attempt at a solution
So, i drew the graph of y against x in my copybook, and circle with origin (0,0), radius = 3 units. The line y = 2x cuts through the circle.
Transforming to polar coordinates, the new limits are:
0≤θ≤tan^-1(3) and 0≤r≤3
[tex]\int\int rdrd\theta[/tex]
After integration, i get the final answer: (9/2)tan^-1(3)
However, the answer in my notes is: (9/2)tan^-1(2). Did i copy the wrong answer or is my work wrong? I'm not sure.
 
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sharks said:
Homework Statement
Find area of regions bounded by
x^2 + y^2 = 9, y = 2x, x-axis in the first quadrant

The attempt at a solution
So, i drew the graph of y against x in my copybook, and circle with origin (0,0), radius = 3 units. The line y = 2x cuts through the circle.
Transforming to polar coordinates, the new limits are:
0≤θ≤tan^-1(3) and 0≤r≤3
[tex]\int\int rdrd\theta[/tex]
After integration, i get the final answer: (9/2)tan^-1(3)
However, the answer in my notes is: (9/2)tan^-1(2). Did i copy the wrong answer or is my work wrong? I'm not sure.

Your answer is wrong, because the following is wrong
...the new limits are:
0≤θ≤tan^-1(3)...​
 
OK, so here is the graph:
http://s2.ipicture.ru/uploads/20111227/zpUVSESp.jpg
From my understanding, i need to find the area of the red section from the graph above.

For θ fixed, 0≤θ≤cos^-1(1/√5) and 0≤r≤3
I checked from calculator and cos^-1(1/√5) = tan^-1(2)

Thanks for your help, SammyS.:smile:
 

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