Find Basis of Perpendicular Vectors for v1 & v2

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SUMMARY

The discussion focuses on finding a basis for all vectors that are perpendicular to the vectors v1 = (1,1,0,0) and v2 = (1,0,1,1) in four-dimensional space. The method proposed involves setting up a linear homogeneous system represented by the matrix equation formed by v1 and v2, ensuring that the dot product with any vector [x,y] results in zero. This approach is confirmed as correct for determining the perpendicular vectors in n-dimensional spaces.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically vector dot products.
  • Familiarity with matrix equations and homogeneous systems.
  • Knowledge of n-dimensional vector spaces.
  • Experience with solving systems of linear equations.
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  • Study methods for solving linear homogeneous systems in n-dimensional spaces.
  • Learn about the geometric interpretation of vector spaces and perpendicularity.
  • Explore the use of matrix rank and null space in determining vector bases.
  • Investigate the application of the Gram-Schmidt process for orthogonalization in higher dimensions.
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Students and professionals in mathematics, physics, and engineering who are working with vector spaces and require a solid understanding of linear algebra concepts, particularly in higher dimensions.

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Homework Statement


how do I find the basis for all vectors that are perpendicular to both
v1 = (1,1,0,0) and
v2 = (1,0,1,1)

If it were 3-D I could find a normal vector via cross product, but in n-dimensions... what do I do?

My one thought is to arrange and solve linear homogeneous system:
[v1][x] = 0
[v2][y] = 0

since RHS is the dot product of the row vector (v1 or v2) and the column [x,y]t, and for vectors to be perpendicular, their dot product should be 0.
Is that correct?

Thanks in advance.
 
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If I understood correctly and you intend to solve the matrix equation

\left(<br /> \begin{array}{cccc}<br /> 1 &amp; 1 &amp; 0 &amp; 0\\<br /> 1 &amp; 0 &amp; 1 &amp; 1<br /> \end{array}<br /> \right)\left(<br /> \begin{array}{c}<br /> x_1&amp;x_2&amp;x_3&amp;x_4<br /> \end{array}\right)=<br /> \left(\begin{array}{c}<br /> 0&amp;0<br /> \end{array}<br /> \right)

then this is what I would do also.
 

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