Find Capacitance from Graph of a Capacitor

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To find capacitance from a capacitor's potential versus time graph, the formula V(t) = V_0e^{-\frac{t}{\tau}} can be used, where τ is the time constant. The easiest way to determine τ is by substituting values of time and voltage from the graph into the equation. Resistance (R) cannot be directly determined from the graph alone, as different combinations of R and C can yield the same curve. Knowing the initial current (I0) can help find R, as I0 equals Vf/R. Understanding these relationships is crucial for analyzing capacitor behavior in circuits.
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My class did a graph of a capacitor. Potential v. time. It showed an exponential curve. How do I find the capacitance by using that graph?

C=t/R but how do I find the resistance?

What must be present to produce a voltage across a capacitor or a resistor?
 
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Did you also learn what the formula for that graph is?

For a discharging capacitor it is:

V(t) = V_0e^{-\frac{t}{\tau }}

There are, if I remember correctly, about four ways to find \tau from that graph, but the easiest method is to pick any point on the graph, and subtitute the values of t and V(t) in the equation above, and you can find \tau, from which you can find C providing you know R.

"What must be present to produce a voltage across a capacitor or a resistor?" -- I don't understand your question.
 
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How do I find resistance with that graph?
 
You can't. R = 5ohm and C = 2μF will give you the same graph as R = 2ohm and C = 5μF. You might be able to find R if you know the inital current in the circuit, I0, which is equal to Vf/R.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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