Find Charge in Sphere: Integrate \rho(r)

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Homework Help Overview

The problem involves calculating the charge enclosed within a sphere of radius R, where the charge density varies as \(\rho(r) = Br^N\). The discussion centers around integrating the charge density and understanding the implications of boundary conditions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to integrate the charge density and questions the validity of their result, particularly regarding the constant of integration and boundary conditions. Some participants suggest using the condition at the center of the sphere instead of the surface. Others inquire about the charge behavior outside the sphere and the relevance of boundary conditions at r=R.

Discussion Status

The discussion is active, with participants exploring different interpretations of boundary conditions and the implications for charge density both inside and outside the sphere. There is no explicit consensus on the correct approach to take regarding the boundary conditions.

Contextual Notes

Participants note that the charge density cannot be zero within the sphere and question the meaning of finding charge density for r greater than R.

YoGabbaGabba
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Homework Statement


In a sphere of radius R, the charge density varies as [tex]\rho[/tex](r) = BrN. There is no charge outside the sphere. B and N are constants.

a.) Find the charge enclosed in a sphere of radius r<R.

Homework Equations


[tex]\rho[/tex]=dq/dv

The Attempt at a Solution


I integrated [tex]\rho[/tex](r)(4[tex]\pi[/tex]r2dr) and got q=(4[tex]\pi[/tex]BrN+3)/(N+3) + C. Is this right? If so, would it be correct to use the boundary condition; @ r=R, q=0 in order to solve for C? It doesn't sound right because there must be charge at the surface?
 
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Hi YoGabbaGabba, welcome to PF,
You are required to find the field at r<R. So you need not the condition r = R. Instead you can take the condition q = 0 at r = 0.
 
Thanks for your time. So if asked to find the charge when r>R, is the charge simply zero or do we consider the boundary conditions r=R? Thanks.
 
YoGabbaGabba said:
Thanks for your time. So if asked to find the charge when r>R, is the charge simply zero or do we consider the boundary conditions r=R? Thanks.
Charge density cannot be zero between r = 0 to r = R. And asking to find the charge density when r > R is meaning less.
 

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