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Find closed form of series SUM (nx)^(2n)

  1. May 1, 2009 #1
    If abs x < 1 find a closed form function (i.e. f(x) = x +1) for the following series:

    [tex]\sum((nx)^(2n))[/tex]

    (reads: the series from n=1 to infinity of nx^(2n))
     
  2. jcsd
  3. May 1, 2009 #2
    Re: Series

    Try to first find an equation for sum n*x^n = x*sum n*x^(n-1) using integration/differentiation.
     
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