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Find closed form of series SUM (nx)^(2n)

  • Thread starter Calculus!
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  • #1
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If abs x < 1 find a closed form function (i.e. f(x) = x +1) for the following series:

[tex]\sum((nx)^(2n))[/tex]

(reads: the series from n=1 to infinity of nx^(2n))
 

Answers and Replies

  • #2
200
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Try to first find an equation for sum n*x^n = x*sum n*x^(n-1) using integration/differentiation.
 

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