Find Current in RC Circuit w/ V=Vo Sin(ωt)

[TheEvenfall]

Hello there, I'm not sure if my solution is correct for \hat{I}_{C}

Homework Statement

In the given circuit, calculate the current in each circuit element given that V = V_{o}sin(ωt)
R, L and C are given.
http://imgur.com/yO3flg8

Homework Equations

Z = R + jX (j^{2} = -1)
X_{L} = jωL
X_{C} = \frac{-j}{ωC}
\hat{V} = V_{o}e^{jωt}
\hat{I} = I_{o}e^{j(ωt-ø)}
I_{o} = \frac{V_{}}{|Z|}
tan(ø) = \frac{\Im(Z)}{\Re(Z)}

The Attempt at a Solution

First for the impedance, 1/Z_{XL} = 1/X_{L} + 1/X_{C}
Z_{XL} = j\frac{ωL}{1- ω^{2}CL}
Z = R + Z_{XL} = R + j\frac{ωL}{1- ω^{2}CL}
The current phasor in the resistor R: \hat{I_{R}}= \hat{I}= \hat{I_{C}} + \hat{I_{L}}
\hat{V_{C}} = \hat{V} - \hat{V_{R}}
\hat{I_{C}} = (\hat{V} - \hat{V_{R}} )/X_{C}
\hat{I_{C}} = (V_{o}e^{jωt} - I_{o}e^{j(ωt-ø)})(jωc) = V_{o}ωCe^{jwt}(1-\frac{R}{|Z|}e^{-jø})(j)
\hat{I_{C}} = V_{o}ωCe^{j(ωt+\pi/2)}(1-\frac{R}{|Z|}e^{-jø}) ø and |Z| are known.
AndI_{L} can be found the same way.
I'm not entirely sure my solution is correct. Also, since I_{R} is always in phase with V, does that mean that ø is 0? If so, then tan(ø) is also 0 but that would mean that either ω or L are 0...

Note: sorry if it seems slobby and for the skipped steps, my exam is in less than 3 hours and I'm really nervous and running out of time.

 

[BvU]

Good luck with your exam! Don't worry too much about this last exercise. The assumption Ir is in phase with V seems incorrect to me.

 

[BiGyElLoWhAt]

well I'm still working through it, but one thing I want to point out is your source voltage is wrong. e^iwc =cos(wc) +isin(wc)
if you want to use eulers id. you want (e^iwc - e^-iwc)/2 , but that seems unnecessary, i'd just keep it v_s or something until you have your final answer, then sub in V(not)sin(wt). also it looks like complex analysis only? no time dependent ? just wondering.