Find Dielectric Constant Given Charges

Click For Summary

Homework Help Overview

The discussion revolves around determining the dielectric constant of a dielectric slab inserted into an air-filled parallel-plate capacitor after it has been charged. The problem involves understanding the relationship between charge, capacitance, and the dielectric constant.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the equations related to capacitance and the dielectric constant, questioning how the dielectric affects charge accumulation. Some express uncertainty about the necessary parameters such as area and distance between the plates.

Discussion Status

Participants are actively engaging with the problem, raising questions about the relevant equations and the implications of inserting a dielectric. There is a recognition that while certain equations are applicable, specific values needed for calculations are missing.

Contextual Notes

Participants note the absence of information regarding the area and distance of the capacitor plates, which complicates the ability to directly calculate the dielectric constant.

Runaway
Messages
48
Reaction score
0

Homework Statement


When a certain air-filled parallel-plate capacitor is connected cross a battery, it acquires a charge (on each plate) of 130 μC. While the battery connection is maintained, a dielectric slab is inserted into and fills the region between the plates. This results in the accumulation of an additional charge of 190 μC on each plate.
What is the dielectric constant of the dielectric slab?

Homework Equations



k = E0/E

The Attempt at a Solution


I have no idea, any guidance as to where to start would be great.
 
Physics news on Phys.org
What's the equation for the capacitance of a parallel-plate capacitor? How does this depend on the dielectric constant?
 
C= k\epsilon0 A / d
so k= C/ (\epsilon0 A / d)
But I still don't have A or d, so how does that help me?
 
Runaway said:
C= k\epsilon0 A / d
so k= C/ (\epsilon0 A / d)

It should be \epsilon, not \epsilon0, if a dielectric is present. The dielectric constant is just k=\epsilon/\epsilon0.

But I still don't have A or d, so how does that help me?
Well, you know that Q=CV for both situations: with the dielectric and without. You also know that V is a constant.
 
ok, so k = q/q0
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
968
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
10
Views
4K
  • · Replies 20 ·
Replies
20
Views
4K
Replies
9
Views
3K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K