Find Displacement/ Velocity/ Acceleration of clock

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Homework Help Overview

The problem involves calculating various vector quantities related to the motion of a clock's minute hand, specifically from the 6 PM mark to the 10 PM mark. The subject area includes concepts from kinematics and circular motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of displacement, average velocity, and average acceleration vectors. There is confusion regarding how to determine average acceleration, particularly in relation to initial and final velocities. Some participants explore the nature of the minute hand's motion and its implications for velocity and acceleration.

Discussion Status

Participants are actively engaging with the problem, with some providing calculations and others questioning the assumptions and definitions involved. There is an exploration of the relationships between the vectors and the nature of circular motion, but no consensus has been reached on the approach to finding average acceleration.

Contextual Notes

There is a noted confusion regarding the compatibility of time intervals with the calculations being performed, as well as the need for clarity on the definitions of initial and final velocities in the context of circular motion.

sakkid95
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A clock has a 20cm minute hand. From the 6PM mark to the 10PM mark, for the tip of the minute hand, calculate:

a) the displacement vector in unit-vector notation
b) the average velocity vector in unit-vector notation
c) the average acceleration vector in unit-vector notation
d) calculate the magnitude and direction of the average acceleration vectorSo I have solved for a is -20cos 30i + 30j
and b is (-20cos 30i+30j)/ 1200 seconds I believe

I really don't understand how you would find the avg acceleration for this problem. I know how to find the magnitude just a^2+b^2= c^2, and I'm not exactly sure how the direction is solved, i think it's tan-1 (Vi/Vf)?

So I just need some help and an explanation on C and how to find the direction. Thanks
 
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To find the average acceleration, you need to have the initial and the final velocities. What are they?
 
I have to calculate it, which is what is confusing me...
 
The tip of the minute hand is in uniform circular motion: what is the direction of its instantaneous velocity at any given hour mark? Its magnitude?
 
I think so, so let's say the minute hand at 6pm is r1 and 10 is r2, so I think v1 would be the vector tangent to r1 would be vi, and vector tangent to r2 is vf. So I believe v1 would be -20x2pi/1200 cm/s= -0.105 cm/s. I'm not sure about v2 though.
 
You have made an attempt to compute the magnitude of velocity at 6 PM. For that, you took the entire length of the minute circle and divided it by 20 minutes. I agree with the entire length, but 20 minutes is not compatible with the entire length. Does the magnitude of instantaneous velocity ever change for the minute hand's tip?

Then, the velocity vector in circular motion is not tangent to the radius vector. It is tangent to the circle of the motion, at the point where motion happens at any given time. It is also evident that the velocity vector is perpendicular to the radius vector.

What are the unit vectors of velocity at 6 PM and 10 PM?
 

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