Find dissipative function for the non-linear force f=-bv^n

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Homework Help Overview

The discussion revolves around finding the dissipative function for a non-linear force described by the equation f = -bvⁿ, where v represents velocity. This falls within the context of Lagrangian mechanics and nonconservative forces.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the formulation of the dissipative function and its relation to the given force. There is a discussion about the correct expression for the force in relation to the dissipative function, with some questioning the notation used.

Discussion Status

The conversation is ongoing, with participants providing feedback on each other's reasoning. There is an acknowledgment of a typo, and one participant expresses agreement with another's interpretation of the dissipative function.

Contextual Notes

There is a mention of a specific form of the dissipative function for a simpler case, which may influence the understanding of the non-linear case being discussed. The discussion also highlights the importance of correct notation in the context of derivatives.

mcconnellmelany
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Homework Statement
For a nonconservative force,
What would be the dissipative function for a force f=-bvⁿ in Lagrangian
(Where v is the velocity)
[#qoute for a nonconservative force f=-bv
The dissipative function is D=-(1/2)bv² ]
Relevant Equations
##\frac{d}{dt}(\frac{\partial L}{\partial \dot x})=\frac{\partial L}{\partial x} - \frac{\partial F}{\partial \dot x}##
For a nonconservative force,
What would be the dissipative function for a force f=-bvⁿ in Lagrangian
(Where v is the velocity)
[#qoute for a nonconservative force f=-bv
The dissipative function is D=-(1/2)bv² ]

Since ##f=\frac{\partial D}{\partial \dot x}## so the dissipative function should be ##D=-\frac{1}{n+1}bv^{1+n}##, isn't it?
 
Last edited:
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mcconnellmelany said:
Since ##f=\frac{\partial D}{\partial \ddot x}##
Do you mean ##f=\frac{\partial D}{\partial \dot x}## ?
 
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haruspex said:
Do you mean ##f=\frac{\partial D}{\partial \dot x}## ?
Hmm! It was a typo.
 
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mcconnellmelany said:
Hmm! It was a typo.
Your answer looks right to me.
 

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