Find dissipative function for the non-linear force f=-bv^n

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SUMMARY

The dissipative function for the non-linear force defined as f = -bvⁿ in Lagrangian mechanics is established as D = - (1/(n+1))bv^(1+n). This conclusion is derived from the relationship f = ∂D/∂ẋ, confirming the correct formulation of the dissipative function for nonconservative forces. The initial suggestion of D = -(1/2)bv² is noted as a specific case for linear damping.

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mcconnellmelany
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Homework Statement
For a nonconservative force,
What would be the dissipative function for a force f=-bvⁿ in Lagrangian
(Where v is the velocity)
[#qoute for a nonconservative force f=-bv
The dissipative function is D=-(1/2)bv² ]
Relevant Equations
##\frac{d}{dt}(\frac{\partial L}{\partial \dot x})=\frac{\partial L}{\partial x} - \frac{\partial F}{\partial \dot x}##
For a nonconservative force,
What would be the dissipative function for a force f=-bvⁿ in Lagrangian
(Where v is the velocity)
[#qoute for a nonconservative force f=-bv
The dissipative function is D=-(1/2)bv² ]

Since ##f=\frac{\partial D}{\partial \dot x}## so the dissipative function should be ##D=-\frac{1}{n+1}bv^{1+n}##, isn't it?
 
Last edited:
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mcconnellmelany said:
Since ##f=\frac{\partial D}{\partial \ddot x}##
Do you mean ##f=\frac{\partial D}{\partial \dot x}## ?
 
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haruspex said:
Do you mean ##f=\frac{\partial D}{\partial \dot x}## ?
Hmm! It was a typo.
 
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mcconnellmelany said:
Hmm! It was a typo.
Your answer looks right to me.
 

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